a. A mirror plane combined with an inversion | ||
b. Two proper rotation axes combined | ||
c. Identity combined with a mirror plane | ||
d. A proper rotation axis combined with a mirror plane | ||
e. The combination of two mirror planes |
a. Polarizability, dipole moment | ||
b. Magnetism, dipole moment | ||
c. Symmetry, magnetism | ||
d. Dipole moment, polarizability | ||
e. Magnetism, symmetry |
a. E | ||
b. C5 | ||
c. i | ||
d. S10 | ||
e. C6 |
a. IR active only | ||
b. Raman active only | ||
c. Both IR and Raman active | ||
d. Neither IR or Raman active | ||
e. The only spectroscopically active mode in the molecule |
a. IR active only | ||
b. Raman active only | ||
c. Both IR and Raman active | ||
d. Neither IR or Raman active | ||
e. The only spectroscopically active mode in the molecule |
a. Both the electronic and vibrational representations must be symmetric. | ||
b. Both the electronic and vibrational representations must be asymmetric. | ||
c. Only the electronic representations must be symmetric. | ||
d. Only the vibrational representations must be symmetric. | ||
e. Symmetry does not matter, as long as there is a change in dipole or polarizability. |
a. Closure (If A and B belong to the group, and A x B = C, then C also belongs to the group.) | ||
b. Associativity (A(BC) = (AB)C ) | ||
c. Identity (The symmetry element times its identity, E, remains unchanged.) | ||
d. Inverses (There must be an inverse symmetry element that returns the molecule to its original state; A x A-1 = E.) | ||
e. Continuity (If a molecule contains an n axis, then it also contains axes of n-1, n-2...) |
a. D2d | ||
b. Cs | ||
c. C2h | ||
d. S4 | ||
e. D4 |
a. H2O | ||
b. BrF5 | ||
c. BH3 | ||
d. PCl6 | ||
e. W(CO)6 |
a. SF6 | ||
b. O2 | ||
c. BF3 | ||
d. C2Cl4 | ||
e. All of the above |
a. Helium also has electrons in antibonding orbitals, resulting in a bond order of zero. | ||
b. Helium also has electrons in non-bonding orbitals, resulting in a bond order of zero. | ||
c. Helium is a noble gas and never forms bonds. | ||
d. Hydrogen also has electrons in nonbonding orbitals, resulting in a bond order of two. | ||
e. Hydrogen has no antibonding orbitals, resulting in a bond order of two. |
a. The amount of magnetic character is reduced in bonds. | ||
b. The electrons are shared between two elements. | ||
c. Nonbonding electrons decrease bond ability. | ||
d. The antibonding electrons interfere with bonding. | ||
e. None of the above |
a. 5 | ||
b. 1 | ||
c. 1.5 | ||
d. 2 | ||
e. 3 |
a. They should be at the same energy to indicate bond formation. | ||
b. They should be at the same energy to indicate allowed symmetry. | ||
c. They should be at different energies, relative to their difference in electronegativities. | ||
d. They should be at different energies, relative to their atomic radii. | ||
e. They should be at different energies, relative to the number of lone pairs of electrons. |
a. A maximum of two electrons per orbital is allowed. | ||
b. The orbitals with the lowest energy are filled first. | ||
c. Orbitals of the same energies are half-filled first; then electrons are allowed to pair up. | ||
d. Non-bonding orbitals are filled first. | ||
e. All of the above |
a. Nonbonding molecular orbitals | ||
b. Antibonding molecular orbitals | ||
c. Bonding molecular orbitals | ||
d. All of the above | ||
e. A and C only |
a. They must have constructive net interaction. | ||
b. They must have the correct symmetry to overlap | ||
c. They must be similar in energy | ||
d. There will be the same number of resultant molecular orbitals as atomic orbitals | ||
e. All of the above |
a. Sigma interactions occur along the internuclear axis. | ||
b. Pi interactions occur above and below the internuclear axis. | ||
c. Sigma bonds form first, followed by the subsequent formation of pi bonds. | ||
d. Two pi bonds are involved in a double bond. | ||
e. All of the above |
a. They are responsible for the formation of pi bonds. | ||
b. They are similar in energy to the atomic orbitals. | ||
c. They counteract bond formation in a molecule. | ||
d. They help hold the molecule together, once it is formed. | ||
e. They are responsible for the formation of sigma bonds. |
a. CO2 | ||
b. H2O | ||
c. CN- | ||
d. Cl2 | ||
e. N2 |
a. Mn2+ | ||
b. V | ||
c. Fe3+ | ||
d. All of the above | ||
e. A and C only |
a. An EPR spectrum shows that oxygen is paramagnetic; MO theory is correct. | ||
b. An EPR spectrum shows that oxygen is paramagnetic; VBT is correct. | ||
c. Infrared spectroscopy shows a double bond stretch; MO theory is correct. | ||
d. Infrared spectroscopy shows a double bond stretch; VBT is correct. | ||
e. There is no way to know which theory is correct in this matter. |
a. There is no actual difference; the orbitals involved are the same, only listed in a different order. | ||
b. The complex having d2sp3 hybridization is an “inner shell” complex, while the complex with sp3d2 hybridization is an “outer shell” complex. | ||
c. The complex having d2sp3 hybridization is an “outer shell” complex, while the complex with sp3d2 hybridization is an “inner shell” complex. | ||
d. The complex having sp3d2 hybridization does not exist; the electrons must fill the lowest energy orbitals first. | ||
e. The complex having d2sp3d2 hybridization does not exist; the electrons must fill the orbitals with the same principle quantum number. |
a. Octahedral | ||
b. Tetrahedral | ||
c. Square planar | ||
d. All of the above | ||
e. Both A and C |
a. They increase their ionization potential, rendering them most useful electrochemically. | ||
b. They reduce degenerate molecular orbitals, allowing a more stable molecule to exist. | ||
c. They undergo a strong magnetic transition, allowing easier detection by NMR and EPR. | ||
d. They increase their transition state energy, making them useful catalysts. | ||
e. They decrease shielding, allowing spectroscopically forbidden transitions to occur. |
a. Yes. The five electrons distribute themselves evenly in the five molecular orbitals, causing them to be degenerate. Axial elongation reduces this degeneracy. | ||
b. Yes. The five electrons distribute themselves evenly in the five molecular orbitals, causing them to be degenerate. Axial compression reduces this degeneracy. | ||
c. No. The five electrons distribute themselves evenly in the five molecular orbitals; no degeneracy exists. | ||
d. No. Four of the electrons are paired. Only one electron is unpaired and can only fill the one remaining orbital. No degeneracy exists. | ||
e. Yes. Four electrons are paired in the lower energy orbitals. The fifth electron can position itself into any of the remaining three orbitals, making it triply degenerate. |
a. mer-bis(cyclopentadienyl)iron(II) | ||
b. fac-bis(cyclopentadienyl)iron(II) | ||
c. bis(η5-cyclopentadienyl)iron(II) | ||
d. µ-bis(cyclopentadienyl)iron(II) | ||
e. (η5-cyclopentadienyl)iron(II) |
a. One would be a solid at room temperature, while the other would be a liquid. | ||
b. One would be highly colored, while the other would be colorless. | ||
c. One would be paramagnetic, while the other would be diamagnetic. | ||
d. One would rotate plane-polarized light clockwise, while the other would rotate it counterclockwise. | ||
e. All of the above |
a. Because the stability gained from having a fully-filled or evenly, half-filled set of d orbitals is greater than the need to fill all lower energy orbitals first | ||
b. Because the 3d orbital is actually lower in energy than the 4s, so it fills first | ||
c. Because copper and chromium only exist as ions; never as neutral elements | ||
d. Because the atomic radii are so large that no effect is felt by the nucleus | ||
e. None of the above |
a. mu (µ) | ||
b. eta (η) | ||
c. chi (χ) | ||
d. xi (ξ) | ||
e. zeta (ζ) |
a. They are malleable and ductile. | ||
b. They have high melting points. | ||
c. They conduct heat and electricity. | ||
d. They are lustrous. | ||
e. They undergo irreversible oxidation. |
a. A low spin, d5 octahedral complex | ||
b. A high spin, d8 octahedral complex | ||
c. A low spin, d3 octahedral complex | ||
d. A d2 tetrahedral complex | ||
e. A d5 square planar complex |
a. Fe(CO)5 | ||
b. Ni(CO)5 | ||
c. Mo(CO)6 | ||
d. Re(CO)6 | ||
e. Ir(CO)5 |
a. The result is a low-spin complex, where electrons will pair up and fill the lowest energy level. | ||
b. The result is a high-spin complex, where electrons will be promoted to the next energy level before pairing. | ||
c. The result is an unstable complex, where electrons can either pair or be promoted to the next energy level. | ||
d. The result is a high-spin complex, where electrons will pair up and fill the lowest energy level. | ||
e. The result is a low-spin complex, where electrons will be promoted to the next energy level before pairing. |
a. BF3 | ||
b. ClF3 | ||
c. PF6 | ||
d. IF5 | ||
e. SbF5 |
a. Charge of the metal ion | ||
b. Nature of the ligands | ||
c. Geometry of the complex | ||
d. Size of the ligands | ||
e. All of the above |
a. [PtCl(H2O)3]Br and [Pt(Br)(H2O)3]Cl | ||
b. cis-[PtCl2(NH3)2] and trans-[PtCl2(NH3)2] | ||
c. [CrCl2(H2O)4]Cl•2H2O and [CrCl3(H2O)3]•3H2O | ||
d. [Co(NH3)6] [Cr(ac)3] and [Co(ac)3] [Cr(NH3)6] | ||
e. [Co(SCN)(NH3)5]- and [Co(NCS)(NH3)5]- |
a. Copper | ||
b. Iron | ||
c. Gold | ||
d. Titanium | ||
e. Tungsten |
a. It is highly polarizable. | ||
b. The ligand is relatively large. | ||
c. The ligand exhibits π donor ability. | ||
d. The ligand is acidic. | ||
e. All of the above |
a. Silver | ||
b. Rhodium | ||
c. Cadmium | ||
d. Molybdenum | ||
e. The melting points would be equivalent, because they are in the same period. |
a. Violet | ||
b. Blue | ||
c. Green | ||
d. Yellow | ||
e. Red |
a. Jahn-Teller distortion | ||
b. Mixing of the p and d orbitals | ||
c. MLCT | ||
d. LMCT | ||
e. All of the above |
a. The spectrum would show one very broad absorption band at 533 nm. | ||
b. The spectrum would show two weak absorption bands, one at 412 nm and the other at 654 nm. | ||
c. The spectrum would show two strong absorption bands, one at 412 nm and the other at 654 nm. | ||
d. The spectrum would show two weak absorption bands, one at 472 nm and the other at 594 nm. | ||
e. The spectrum would show two strong absorption bands, one at 472 nm and the other at 594 nm. |
a. The ligand field stabilization energy (LFSE) is insufficient to allow transitions to the left of the line. | ||
b. The transitions to the left are symmetry allowed, while the transitions to the right are spin allowed. | ||
c. The transitions to the left are spin allowed, while the transitions to the right are symmetry allowed. | ||
d. The transitions to the left are low-spin complexes, while the transitions to the right are high-spin complexes. | ||
e. The transitions to the left are high-spin complexes, while the transitions to the right are low-spin complexes. |
a. Two | ||
b. Three | ||
c. Nine | ||
d. Six | ||
e. Zero |
a. CT absorptions occur at higher wavelengths than d-d transitions. | ||
b. CT absorptions are less intense than d-d transitions. | ||
c. CT transitions are symmetry and spin allowed; d-d transitions are symmetry forbidden. | ||
d. CT transitions are spin allowed; d-d transitions are spin forbidden. | ||
e. CT transitions are symmetry and spin forbidden; d-d transitions are symmetry forbidden but spin allowed. |
a. Zn2+ has a completely filled d orbital, and Sc3+ has a completely empty d orbital. | ||
b. Zn2+ and Sc3+ always form high spin octahedral complexes. | ||
c. Zn2+ and Sc3+ always form low spin octahedral complexes. | ||
d. Zn2+ and Sc3+ are diamagnetic; the others are paramagnetic. | ||
e. Zn2+ and Sc3+ are paramagnetic; the others are diamagnetic. |
a. The transition in the high spin complex is symmetry and spin forbidden. The transition in the low spin complex is symmetry allowed. | ||
b. The transition in the high spin complex is symmetry and spin forbidden. The transition in the low spin complex is spin allowed. | ||
c. The transition in the high spin complex is symmetry forbidden but spin allowed. The transition in the low spin complex is symmetry and spin allowed. | ||
d. The transition in the high spin complex is spin forbidden but symmetry allowed. The transition in the low spin complex is symmetry and spin allowed. | ||
e. The transition in the high spin complex is symmetry and spin forbidden. The transition in the low spin complex is symmetry and spin allowed. |
a. The solution containing cyanide ion will give a larger crystal field splitting, causing a blue shift in the color of the complex. The complex with thiocyanate ion will appear as more red shifted. | ||
b. The solution containing cyanide ion will give a smaller crystal field splitting, causing a blue shift in the color of the complex. The complex with thiocyanate ion will appear as more red shifted. | ||
c. The solution containing cyanide ion will give a larger crystal field splitting, causing a red shift in the color of the complex. The complex with thiocyanate ion will appear as more blue shifted. | ||
d. The solutions will both be similar in color; however, the complex with thiocyanate will be more intense. | ||
e. You cannot tell them apart; the experiment would need to be restarted. |
a. Dynamic fluxionality | ||
b. Spin-spin coupling interactions | ||
c. Integer quantum spin numbers (I = 1,2,3…) | ||
d. Fractional quantum spin numbers (I = 1/2, 3/2, 5/2) | ||
e. Low natural abundances of the 19F nucleus |
a. The asymmetric stretch of the C-O bonds creates a dipole moment that is IR active. | ||
b. The symmetric stretch of the C-O bonds creates a dipole moment that is IR active. | ||
c. The non-linear bending mode crates a net dipole, which is IR active. | ||
d. All of the above | ||
e. A and C only |
a. The chemical shift and resonance frequency also change. | ||
b. The chemical shift changes; the resonance frequency remains constant. | ||
c. The chemical shift remains constant; the resonance frequency changes. | ||
d. The chemical shift and resonance frequency remain constant. | ||
e. There is no way to predict the effect. |
a. The Zeeman effect | ||
b. Pauli exclusion principle | ||
c. Symmetry degeneracy | ||
d. Fermi contact interaction | ||
e. Bose-Einstein effect |
a. Dissociation and recoordination of the carbonyl ligands | ||
b. Rotation of a hindered carbonyl bond | ||
c. Opening and closing of bridging carbonyls | ||
d. Isomerism between trigonal bipyramidal and square pyramidal configurations | ||
e. Monmer-dimer formation with a bridging carbonyl |
a. NO2 radical | ||
b. CH3 radical | ||
c. CH2Cl radical | ||
d. CH2CH2 radical | ||
e. OH radical |
a. Paramagnetic transition metal complexes | ||
b. Diamagnetic transition metal complexes | ||
c. Free radicals in the solid state | ||
d. Free radicals in the liquid or gas state | ||
e. Complexes containing more than one unpaired electron |
a. An odd mass number and odd atomic number, such as 1H | ||
b. An odd mass number and an even atomic number, such as 13C | ||
c. An even mass number and an even atomic number, such as 16O | ||
d. An even mass number and an odd atomic number, such as 14N | ||
e. All of the above situations will result in a nonzero quantum spin number. |
a. A free electron | ||
b. An unpaired electron in an organic molecule | ||
c. An unpaired electron in a transition metal complex | ||
d. All of the above | ||
e. A and B only |
a. Cationic metal complexes experience less π backbonding than their neutral or anionic analogs. | ||
b. Pyridine is a good π acceptor and contributes to increased π backbonding. | ||
c. The carbonyl to metal bond strength is increased in the chloro complex. | ||
d. All of the above | ||
e. A and B only |
a. Two; through the lone pairs on the two nitrogen atoms | ||
b. Two; through the lone pairs on two of the oxygen atoms | ||
c. Four; through the lone pairs on the four oxygen atoms | ||
d. Four; through the anion on the four oxygen atoms | ||
e. Six; two through the lone pairs on the two nitrogen atoms and four through the lone pairs of the four oxygen atoms |
a. Associative mechanism, aided by a ring slip | ||
b. Dissociative mechanism, in which the Cp ring is lost | ||
c. Inversion of stereochemistry and loss of the Cp ring | ||
d. Dissociation of the Cp ligand, followed by re-association of Cp | ||
e. All of the above |
a. It is dependent on which ligands are a part of the primary valence and which ones are a part of the secondary valence. | ||
b. It depends on the charge of the metal ion present. | ||
c. It depends on the number of empty d orbitals. | ||
d. It depends on the nature of the ligands involved and whether they are mono or multi-dentate. | ||
e. All of the above |
a. 2 | ||
b. 5 | ||
c. 6 | ||
d. 8 | ||
e. 10 |
a. 2 | ||
b. 3 | ||
c. 4 | ||
d. 5 | ||
e. 6 |
a. +3 | ||
b. +2 | ||
c. +4 | ||
d. +7 | ||
e. +6 |
a. It plays an important role in insertion, polymerization, and metathesis reactions. | ||
b. It describes a complex with a coordination number less than 4. | ||
c. It generally means another ligand can be accommodated. | ||
d. All of the above | ||
e. A and C only |
a. [Co(Cl3)](NH3)6; AgCl is formed. | ||
b. [Co(Cl3)](NH3)6; NH4Cl is formed. | ||
c. [Co(NH3)6]Cl3; AgCl is formed. | ||
d. [Co(NH3)6]Cl3; NH4Cl is formed. | ||
e. Both will react with silver in water; AgCl and NH4Cl are formed. |
a. EDTA | ||
b. SCN- | ||
c. NH3 | ||
d. Hemoglobin | ||
e. Cl- |
a. Hydrophilic interactions | ||
b. Hydrophobic interactions | ||
c. Van der Waals interactions | ||
d. Lewis acid-base interactions | ||
e. Hydrogen bonding interactions |
a. Fe(s) | ||
b. Fe3+(aq) | ||
c. Fe(OH)2(s) | ||
d. Fe2+(aq) | ||
e. Fe(OH)3(s) |
a. The species on the left is readily reduced to the species on the right side of the arrow. | ||
b. The species on the lef tis a good reducing agent. | ||
c. The species under goes diproportionation. | ||
d. All of the above. | ||
e. None of the above. |
a. The heat of formation of the precursor complex | ||
b. The heat of fission of the successor complex | ||
c. The solvation energy of the transition complex | ||
d. The free energy of electron transfer | ||
e. All of the above |
a. The reaction does not proceed. | ||
b. The reaction is drastically slowed, requiring a spin flip to occur. | ||
c. The reaction proceeds quicker, because different spin states allow faster electron transfer. | ||
d. The reaction will proceed as inner sphere instead, because electrons with different spin will pair and form a bond. | ||
e. None of the above |
a. Even though a reaction is thermodynamically favorable, the reaction may be slow kinetically. | ||
b. All redox reactions are favorable at in alkaline media. | ||
c. All thermodynamically favorable reactions occur quickly on a kinetic scale. | ||
d. If a reaction is kinetically favorable, it will proceed even if it is thermodynamically unfavorable. | ||
e. No redox reactions occur in highly acidic media. |
a. Formation of the bridging ligand complex | ||
b. Formation of the precursor (cage) complex | ||
c. Electron transfer | ||
d. Solvent entering the coordination sphere | ||
e. Fission of the successor ligand complex |
a. Formation of the bridging ligand complex | ||
b. Fission of the successor ligand complex | ||
c. Electron transfer | ||
d. Solvent entering the coordination sphere | ||
e. Both B and C |
a. H3PO4 | ||
b. NH4+ | ||
c. HNO3 | ||
d. PH3 | ||
e. P & N (elemental) |
a. They experience Jahn-Teller distortion, making their axial bonds longer and easier to break. | ||
b. Their ground state structure resembles their transition state structure. | ||
c. Their electrons are distributed equally among the d-orbitals. | ||
d. Their large radii can accommodate a larger coordination sphere. | ||
e. Both A and B |
a. Tetragonal | ||
b. Trigonal bipyramidal | ||
c. Square pyramidal | ||
d. Both A and C | ||
e. All of the above |
a. The trans influence | ||
b. The trans effect | ||
c. The biphilic effect | ||
d. The solvolysis effect | ||
e. The anation effect |
a. Enthalpy of reaction | ||
b. Decreased activation energy | ||
c. Formation of dimeric species (bridging ligands) | ||
d. Entropy of reaction | ||
e. Outer sphere electron transfer |
a. The chloride ions are larger than the water molecules, only allowing four to coordinate around the central metal ion; ammonia is similar in size to water, so six will coordinate. | ||
b. The chloride ions are anionic, and the metal centers cannot accommodate a larger negative charge; ammonia is a neutral species. | ||
c. Chloride ions precipitate the metals out of solution; ammonia complexes do not. | ||
d. The addition of excess chloride ions will actually result in hexa-chloro compounds. | ||
e. Chloride additions occur in acidic media; ammonia is alkaline. |
a. The entering group | ||
b. The leaving group | ||
c. Other ligands in the coordination sphere | ||
d. The metal center itself | ||
e. All of the above |
a. It is a kinetic phenomenon. | ||
b. It can influence M-L bond lengths. | ||
c. It can result in changes in NMR coupling constants. | ||
d. It can affect the vibrational frequency. | ||
e. It is purely thermodynamic. |
a. They occur via an associative mechanism with a five coordinate intermediate. | ||
b. They only proceed when bond formation is the rate determining step. | ||
c. They only proceed when bond breaking is the rate determining step. | ||
d. They only proceed when the transition energies of bond formation and bond breaking are similar. | ||
e. They occur via a dissociative mechanism with a three coordinate intermediate. |
a. k = [A][B] | ||
b. k = [A] | ||
c. k = [A]2[B] | ||
d. Both A and C | ||
e. The mechanism cannot be determined from the rate law. |
a. Activation energy | ||
b. Thermal energy | ||
c. Electron transfer | ||
d. Entropy | ||
e. Enthalpy |
a. Ammonia | ||
b. Sulfur trioxide | ||
c. Sulfuric acid | ||
d. Margarine | ||
e. Nitric acid |
a. Ammonia | ||
b. Sulfur trioxide | ||
c. Sulfuric acid | ||
d. Margarine | ||
e. Nitric acid |
a. It shifts the equilibrium toward the products based on LeChatlier’s principle. | ||
b. It provides an alternate route with a lower activation energy for the reaction to proceed. | ||
c. It donates electrons to break or form bonds as needed until it is entirely consumed. | ||
d. It forms bridging complexes which align the molecular orbitals of the reactants. | ||
e. All of the above |
a. The hydrogenation of vegetable oil in the presence of nickel to make margarine | ||
b. The use of Pt, Pd or Rh in catalytic converters | ||
c. The destruction of ozone in the atmosphere | ||
d. The use of vanadium(V)oxide in the conversion of sulfur dioxide to sulfur trioxide | ||
e. All of the above |
a. Ru | ||
b. Ti | ||
c. V | ||
d. Fe | ||
e. All of the above |
a. Doping allows the LED to harvest light from triplet states, increasing quantum efficiency. | ||
b. Doping increases the overall number of singlet to singlet emission pathways. | ||
c. It reduces the overall cost of producing an LED; the inorganic dopants are inexpensive. | ||
d. All of the above | ||
e. None of the above |
a. Metal ion complexes are unable to harvest light energy. | ||
b. The cost of the metal ion complexes is prohibitive. | ||
c. The storage of energy occurs by thermal or chemical means. | ||
d. The energy produced can only be utilized in electrical grids. | ||
e. All of the above |
a. Nickel-cadmium in portable electronics and toys | ||
b. Lead acid batteries in automobiles | ||
c. Silver-zinc button cells in hearing aides | ||
d. Silver-cadmium batteries in satellites | ||
e. Zinc-carbon dry cell batteries in flashlights |
a. The organometallic complexes are easier to synthesize than the inorganic salts. | ||
b. The organometallic complexes are less toxic and more effective in lowering blood glucose levels. | ||
c. The organometallic complexes are less expensive to synthesize and cost less on the market. | ||
d. The effect of the inorganic salts was discovered after the organometallic complexes had established a successful history. | ||
e. The FDA will not approve medicinal use of purely inorganic compounds for biological applications. |
a. Metals are nontoxic to humans. | ||
b. Harmful stereoisomers do not exist. | ||
c. They are soluble in water and easily administered. | ||
d. They counteract drug resistance that has been built to purely organic molecules. | ||
e. There are no current organometallic applications to antimicrobials. |